5. Реши уравнения. x + (26 + 15) = 56; 5 - a = 45; 99a = 100 - 82; c - (47 - 27) = 59; b : 5 = 8; 32 : x = 4.

Решим по порядку.

1) \(x + (26 + 15) = 56\)

\(26 + 15 = 41\), значит \(x + 41 = 56\)

\[ x = 56 - 41 = 15 \]

2) \(5 - a = 45\)

\[ a = 5 - 45 = -40 \]

3) \(99a = 100 - 82\)

\(100 - 82 = 18\), значит \(99a = 18\)

\[ a = \frac{18}{99} = \frac{2}{11} \]

4) \(c - (47 - 27) = 59\)

\(47 - 27 = 20\), значит \(c - 20 = 59\)

\[ c = 59 + 20 = 79 \]

5) \(b : 5 = 8\)

\[ b = 8 \cdot 5 = 40 \]

6) \(32 : x = 4\)

\[ x = 32 : 4 = 8 \]

Ответ: \(x = 15\); \(a = -40\); \(a = \frac{2}{11}\); \(c = 79\); \(b = 40\); \(x = 8\).

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