Решите уравнение 1) х+7/12= 3/4 2) х-1/6=1/9 3) х-3/5=3/8 4) х+5/24=7/12

1) \[x+\frac{7}{12}=\frac{3}{4}\]
\[x=\frac{3}{4}-\frac{7}{12}=\frac{9}{12}-\frac{7}{12}=\frac{1}{6}\]

2) \[x-\frac{1}{6}=\frac{1}{9}\]
\[x=\frac{1}{9}+\frac{1}{6}=\frac{2}{18}+\frac{3}{18}=\frac{5}{18}\]

3) \[x-\frac{3}{5}=\frac{3}{8}\]
\[x=\frac{3}{8}+\frac{3}{5}=\frac{15}{40}+\frac{24}{40}=\frac{39}{40}\]

4) \[x+\frac{5}{24}=\frac{7}{12}\]
\[x=\frac{7}{12}-\frac{5}{24}=\frac{14}{24}-\frac{5}{24}=\frac{3}{8}\]

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